Homework Statement
Ok I have two questions.
1. Light waves of which wavelength will destructively interfere due to the thickness of the bubble film? The bubble film thickness is 165 nm, with an index of refraction of n = 1.3.
a= 430 nm
b= 650 nm
c= 860 nm
d= 285 nm
2. You are...
Homework Statement
If the be Broglie wavelength associated to the first orbit of the electron inside the atom of hydrogen is 62.4 nm, what is the wavelength associated to the fourth orbit?
1. 62.4 nm
2. 124.8 nm
3. 312 nm
4. 249.6 nm
Homework Equations
# of...
Homework Statement
Using the uncertainty principle find the energy required for the electron to be confined inside the hydrogen atom. Use the radius of the atom 1 x 1010 m for Δr. Express your answer in eV, rounded up to the nearest hundredth.
Homework Equations
ΔxΔp\geqh/4pie...
Homework Statement
Using the uncertainty principle find the energy required for the electron to be confined inside the hydrogen atom. Use the radius of the atom 1 x 10^10 m for Δr. Express your answer in eV, rounded up to the nearest hundredth.
Homework Equations
Δx(Δp)\geqh/4pie
x=...
alright.
so i solved for n and i got 1.08 and since only integers are accepted i would round off to 1 right?
and since k=1 and n=1 how do i know whether it is absorbing or not?
and how could i solve with the other equation? once i found the energy of the photon what would i do after?
o ok. well the energy of the photon would be hc/lambda which would be 2.1 eV nm but why do we need this?
i thought that you could just find n by putting in lambda and k (fundamental state) on the 1/lambda=1/k^21/n^2 and solving for n
ok appreciate your help. heres the question
A photon with λ = 600 nm interacts with a hydrogen atom in fundamental state. Will the photon be absorbed? Justify your answer.
and btw im homeschooled and im taking the ut austin high school program, and we dont get text books but its an online...
Homework Statement
ok so i know whenever a photon is absorbed it will jump up a energy level and when it is emmited it releases energy. but my question is, for example, if k=1 (fundamental state) in a hydrogen atom and they give you the given wavelength of the photon, you solve it and you...
o ok.
but if k=1 and i get n=1.08 and since only integers are accepted would it round off to 1 and not absorb? or since it is a larger number than 1 it would absorb?
btw
if it absorbs, would the rest of the energy that was left that didnt absorb turn into kinetic energy?
Homework Statement
how can i tell if a photon is being emmited or absorbed?
Homework Equations
hc/lambda= energy per photon
1/lambda=r(1/n^21/k^2)
The Attempt at a Solution
photons are absorbed when the energy of the photon= energy of transition?
when are they emmited?
and i...
o ok.
stupid me i see what i did now.
and btw
how do you know when a photon is absorbing energy?
is it when the photon energy is the same to the energy transition? but im kind of confused because i thought they were always equal to each other
o ok. so this wouldnt absorb, because if n is equal to 1 it still wouldnt absorb because the energy of transition would not be equal to energy of the photon right?
hf= 2.1
energy of transition (if n=1) i= 0
and a number like 1.08 could not be used only integers right?
so that is why is no...
Homework Statement
The wavelength of the photon emitted when a hydrogen atom undergoes a transition from the k state to the n = 1 state is around 94.8 nm. How much is k?
Homework Equations
1/lambda= 1.97x10^7(1/1^21/k^2)
The Attempt at a Solution...
ok so if its off by .08 to being a integer it wont absorb??
and you said that energy of photon has to be equal to transition energy to absorb...
but isnt it always equal??
because photon= hc/lambda, but energy transition= the same thing.
so doesnt this say that it ALWAYS absorbs because it will...
o so is it supposed to be R(1/1^21/n^2)??
i put R(1/2^21/n^2) because i assumed it was in the visible light (balmer series) because 600 nm is visible light.
o ok. so..
1/6x10^7=1.097x10^7(1/2^21/n^2)
.1519295047=11/n^2
1.179147259=n^2
1.08=n
so since n=1 that means that it will absorb because it is the same energy as the fundamental state?
btw.
what if it was larger like n=2? would that mean it emits part of the photon into kinetic...
Homework Statement
A photon with λ = 600 nm interacts with a hydrogen atom in fundamental state. Will the photon be absorbed? Justify your answer.
Homework Equations
hc/lambda= energy of photon
1/lambda= R(1/2^21/n^2) (visible light)
c= speed of light
lambda= wavelength
h=...
ok i think i got it. how does this look
4.14x10^15(c/5x10^8)= 24.84 eV
24.4813.6= 11.24 eV of excess kinetic energy
and it would ionize because it is now positive.
and for B would i just do the same thing but in joules?
6.6x10^34(c/5x10^8)= 3.96^18
3.96^182.178961169x10^18= 1.78x10^18...
ok.
so what if its in a bound state,
doesnt it need to jump from a bound state to a free state to be an integer because it needs to have a positive value.
and i used the formula that you showed me, but what is h?
i just did neu=c/lambda13.6 and i got 1.1 but that is not the kinetic energy cus...
ooo ok. i understand the question now, but would 1.1 just round off to 1? and if it would how is that ionized, if the electron has eV? and if it doesnt round off then what would happen because i know only integers are for n.
and for b? because i know to find the energy of the orbit is 13.6...
Homework Statement
A hydrogen atom has an electron in the fundamental state.
a. Show that a radiation with λ = 50 nm will ionize the atom.
b. What will be the excess kinetic energy of the electron in joules?
Round up your answer to the nearest hundredth.
Homework Equations
1/lambda=...
yes ive already seen it in wikipedia and hyperphysics, i understand the whole concept im just not sure what the answer would be. I know bohrs model represents how negative charged electrons encircle the positive and might jump back or fourth a orbit depending on the electromagnetic energy it...
Homework Statement
In Bohr’s quantum model of the atom:
1. The energy of an electron inside the atom is an integral multiple of 13.6eV.
2. Electrons lose energy and spiral into the nucleus.
3. Gravitational forces are offset by electric forces.
4. Electrons do not radiate...
o ok i think that should work i was doing it by inserting
9
x
10
^

31
so i think your way should work.
thanks for the replies and for helping me out with my question